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C Code Generator

Text generator - C code generation examples

Example input

  • #include <stdio.h> int main() { printf(

Example real generated results

  • star

    "\n\n%d\n", sizeof(int)); printf("\n\n%d\n", sizeof(void *)); printf("\n\n%d\n", sizeof(char)); printf("\n\n%d\n", sizeof(int *)); printf("\n\n%d\n", sizeof(char *)); printf("\n\n%d\n", sizeof(int (*)(int)) ); printf("\n\n%d\n", sizeof(char (*)(char)) );

  • star

    "\n\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n"); printf("\n\n\n\n");

  • star

    "hello world\n"); return 0; } A: The problem is that your program is using a non-const variable. When you call printf("hello world");, the compiler is trying to compile the printf into a function call. However, the compiler doesn't know that hello world is a constant, so it can't know that it will be evaluated once. You can fix this by declaring the variable as const. #include <stdio.h> int main() { const char *hello

  • star

    "%d\n", sizeof(char)); return 0; } Output of the above code is: 1 4 This is correct as sizeof(char) = 1, and sizeof(char *) = 4. In other words, char * is an array of char, and char is an array of 1 character. But if we change char * to char (which is an array of 1 character), we get a different result as shown below: printf("%d\n", sizeof(char))

try it yourself: Text Generator Playground - C Code Generator